Maths Help, Please!

[Vella_Malachite]

Hi. Given the expertise level here, I thought I'd tap into the collective mind of the Playground for this one :smallbiggrin:

Well, I'm just studying for my exam, and I realised I'd forgotten how to do this one type of question :smallyuk:. When it is solved, could there be an explanation to accompany it, please?

The question is:

(a^2n-1*b^3*c^1-n)/(a^n-3*b^2-n*c^2-2n)

Thanks in advance!

[GoC]

A. :smallsigh: (http://lmgtfy.com/?q=algebra+math+help) or :smallyuk: (http://answers.yahoo.com/)
B. That's not a question
C. If you thought for a moment about what those symbols represent the answer would be instantaneous. As it is you're just proving my point (http://www.giantitp.com/forums/showthread.php?t=126540).

[Assassin89]

Your question is equivalent to a^(n+2)*b^(n+1)*c^(n-1)

Essentially when dividing exponents, group the like terms and subtract the exponents.

By grouping a, the equation a^(2n-1)/a^(n-3) = a^(2n-1-(n-3))= a^(2n-1-n+3)= a^(n+2)