View Full Version : pH of mixed acid solutions
Prodan
2010-06-01, 07:38 AM
Don't suppose anyone can give me any pointers on solving this problem?
"What will the approximate pH of a buffer prepared by mixing 100 mL of 0.1M NaHPO4 and 100 mL of 0.1M NaH2PO4? (For H3PO4, pKa1 = 2.1, pKa2 = 6.8, pKa3 = 12.5)"
I've been trying to figure it out for a while, but I can't remember enough about mixed solutions, and I'm not finding the examples in my textbook helpful.
Cyrion
2010-06-01, 09:23 AM
Have you tried using the Henderson-Hasselbalch equation? Calculate the initial concentrations of your acid and base, choose the correct pKa (should be pKa2) and plug and chug.
Nomrom
2010-06-01, 10:43 AM
Fro some reason it makes me feel better, knowing that people from all over say plug and chug.
Mando Knight
2010-06-01, 10:45 AM
Who doesn't?
Prodan
2010-06-02, 03:17 AM
Have you tried using the Henderson-Hasselbalch equation? Calculate the initial concentrations of your acid and base, choose the correct pKa (should be pKa2) and plug and chug.
Alright, I figured out the problem. Turns out I made an error when checking the answer and looked at the wrong problem...
Superglucose
2010-06-02, 03:33 AM
Don't suppose anyone can give me any pointers on solving this problem?
"What will the approximate pH of a buffer prepared by mixing 100 mL of 0.1M NaHPO4 and 100 mL of 0.1M NaH2PO4? (For H3PO4, pKa1 = 2.1, pKa2 = 6.8, pKa3 = 12.5)"
NaHPO4 should be NaHPO4- because PO4 is 3- not 2-. That means we have a buffer solution of conjugate base and its conjugate acid, rather than a mixed solution.
Initial concentrations are all we really need. Also the pKa of H2PO4- is 7.2 in the value I found.
So pH = 7.2 + log [1]/[1] = 7.2
Prodan
2010-06-02, 03:39 AM
The problem gives it as 6.8 for both the answer and the pKa.
Deth Muncher
2010-06-02, 03:58 AM
Fro some reason it makes me feel better, knowing that people from all over say plug and chug.
Agreed. :smallsmile:
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