[3.5] BAB question

[questionmark693]

I take six levels of fighter, my BAB is +6/+1. If I start multiclassing, does my second attack not get better because the other class only gets +1? How does that work?

[Amnestic]

You mean your second iterative? If you take a second class with full BAB, then your 7th level will give you +7/+2 BAB.

[Garagos]

Always add the new class' BAB to your highest BAB (non-iterative) number. Then just keep your iteratives in increments of 5 below the highest one.

For example, a Fighter9/Wizard4/Rogue6 would have a BAB of +14 plus two iterative attacks at +9 and +4 (+14/+9/+4).

[Namfuak]

Ignore the / for a second. Your full BAB increases by the amount given by the class at the level of the class you have taken. For a fighter, they get 1 BAB each level, so a 6th level fighter has 6 BAB. Adding a level of barbarian, which also gains 1 BAB per level, will bring your total BAB to 7. Adding a level of rogue to this would not add a BAB at first, because rogues only get 3/4 BAB per level, and you round down. A second rogue level will add a BAB, or another level of barbarian or fighter (if you are playing with fractional BAB, any class will add another BAB at this point, but that's usually not the case). So, a Fighter 6/Barb 1/Rogue 1 has 7 BAB, while Fighter 6/Barb 1/Rogue 2 has 8.

The /+1 is just your iterative attack. Once your total BAB between classes is 6, you get another attack which adds your total BAB-5 to it. Every 5 BAB thereafter, you get another attack, each time losing another 5 BAB to the attack (so if you were only taking full BAB classes, you would get another at level 11, and one more at level 16).

[questionmark693]

That makes so much more sense than what I was trying to figure out, thank you so much!

[Shining Wrath]

As a note, there are only 10 or so base classes with full BAB progression.