Uncanny Trickster

[badgerman]

This is not about creating the most powerful character, it's just about being legal or not!

Is this a legal build ?

Level Class
1st - 5th e.g. Rogue
6th Fortune's Friend 1
7th Fortune's Friend 2
8th Uncanny Trickster 1
9th Uncanny Trickster 2 [Fortune's Friend 3]
10th Fortune's Friend 4
11th Uncanny Trickster 3 [Fortune's Friend 5]

Asking because of:
1. Fortune's Friend (FF) has a bad BAB Uncanny Trickster (UT) a medium BAB. By substituting FF 3 and 5 with UT 2 and 3 BAB should be +4 / 6 Level. So upgrading from bad to medium BAB.
2. UT gives 8 skill-points and has got more class-skills than FF.
3. One more level for 3 x bonus trick, 3 x favorite trick and tricky defense.

Thanks

[OldTrees1]

Uncanny Trickster progresses class features of the selected class. You would still have the BAB of Rog5(+3) + FF 3(+1) + UT 3(+2) = +6 at 11th level.

[Urpriest]

Uncanny Trickster progresses class features of the selected class. You would still have the BAB of Rog5(+3) + FF 3(+1) + UT 3(+2) = +6 at 11th level.

BAB isn't a class feature. Edit: Nevermind that's what you were saying. Anyway, the rest should put this in more detail for the OP:

You don't actually get to skip levels of Fortune's Friend, you just get class features as if you were higher level. So your build would go as:

1st - 5th Rogue (Not e.g., specifically Rogue) BAB +3
6th Fortune's Friend 1 BAB +3
7th Fortune's Friend 2 BAB +4
8th Uncanny Trickster 1 BAB +4
9th Uncanny Trickster 2 [class features of Fortune's Friend 3] BAB +5
10th Fortune's Friend 3, class features of Fortune's Friend 4 BAB +5
11th Uncanny Trickster 3 [class features of Fortune's Friend 5] BAB +6

Note that all this changes if you're using fractional BAB. I've been assuming you're not, since you would have mentioned it in the OP if you were. If your DM is using fractional BAB, the progression instead works as follows:

1st - 5th Rogue BAB=5*3/4->+3
6th Fortune's Friend 1 BAB=5*3/4+1/2->+4
7th Fortune's Friend 2 BAB=5*3/4+2/2->+4
8th Uncanny Trickster 1 BAB=6*3/4+2/2->+5
9th Uncanny Trickster 2 [class features of Fortune's Friend 3] BAB=7*3/4+2/2->+6
10th Fortune's Friend 3, class features of Fortune's Friend 4 BAB=7*3/4+3/2->+6
11th Uncanny Trickster 3 [class features of Fortune's Friend 5] BAB=8*3/4+3/2->+7

[badgerman]

Thanks a lot

[badgerman]

9th Uncanny Trickster 2 [class features of Fortune's Friend 3] BAB +5
10th Fortune's Friend 3, class features of Fortune's Friend 4 BAB +5
11th Uncanny Trickster 3 [class features of Fortune's Friend 5] BAB +6

Maybe a stupid question, but I can't find the rule which states that you gain class-features of the following class-level if you already got the class-features of your actual level.

So may it be that you should not take any levels of a class in which you already advanced in class-features or just gain its BAB-, save-, hd- and skill-advancement?

[Urpriest]

Maybe a stupid question, but I can't find the rule which states that you gain class-features of the following class-level if you already got the class-features of your actual level.

So may it be that you should not take any levels of a class in which you already advanced in class-features or just gain its BAB-, save-, hd- and skill-advancement?

Remember, PrC abilities don't just happen once, they're continuous. When Uncanny Trickster says that you gain class features as if you had gained a level in your previous class, it doesn't just mean when you take that level, it means whenever you have to figure out what class features you have. So if you have three levels of Fortune's Friend and two levels of Uncanny Trickster, then you have class features as if you were a Fortune's Friend 4, no matter the order of the levels involved.