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darkriku2000
2007-09-29, 11:14 PM
so, me and my bro started a d&d campaign a while back, and i was looking at the dusk blade spells, and one some of them seem to use d3 rolls, we don't have a 3 sided die, infact, i don't think one even exists, how would we do this roll?:smallconfused:

Nermy
2007-09-29, 11:16 PM
Roll a six sided die:

1-2 = 1

3-4 = 2

5-6 = 3

Justyn
2007-09-29, 11:22 PM
Actualy, d3s do exist (http://www.gamestation.net/c=kUd2f2sxBtyY5j7WFvtEJMMEA/product/CHXXT0307/Precision_Amethyst_d3.html); they are just pretty uncommon. But dividing the d6 roll in half works, too.

Ralfarius
2007-09-29, 11:25 PM
Find a copy of that board game, Siege. You know, the one where you fire the orange marbles at each other's castles/forts/etc and try to knock down their little plastic men?

Anyhow, Siege has regular D6's, except they only have the numbers 1, 2, and 3 on their faces. The only trick is that 1 only appears once and 3 appears thrice. Simply take a permanent mark and place a dot on one of the faces with 3 (or colour in the 3 if you prefer).

There you have it! A perfectly functioning 3-sided die. And it's much more complicated than simply rolling a regular D6, dividing by 2, and rounding up. Therefore, it must be better!

AslanCross
2007-09-29, 11:32 PM
You could roll a d6 and count 1-2 as 1, 3-4 as 2, and 5-6 as 3. And there are d3s, they're barrel shaped or something.

The Extinguisher
2007-09-30, 01:44 AM
Actualy, d3s do exist (http://www.gamestation.net/c=kUd2f2sxBtyY5j7WFvtEJMMEA/product/CHXXT0307/Precision_Amethyst_d3.html); they are just pretty uncommon. But dividing the d6 roll in half works, too.

Fancy.

But a d6 in half, or 1-2 as 1, 3-4 as 2, and 5-6 as 3 is probably easier that buying those dice.

Rex Blunder
2007-09-30, 09:31 AM
Cut a d6 in half using a bandsaw. From a single d6 you can get 2 d3s; 4 from a d12; and from a d20 you can get 2 d3s, a d5, a d7, and a d2.

Green Bean
2007-09-30, 09:39 AM
Cut a d6 in half using a bandsaw. From a single d6 you can get 2 d3s; 4 from a d12; and from a d20 you can get 2 d3s, a d5, a d7, and a d2.

Of course! Brilliant! :smallbiggrin:

Curmudgeon
2007-09-30, 10:36 AM
Cut a d6 in half using a bandsaw. From a single d6 you can get 2 d3s Yeah, that's easy. But it does require a Möbius band saw. :smallwink:

Rex Blunder
2007-09-30, 10:59 AM
Nah, just the non-euclidean bandsaw of Yug-Shoggoth, the Shop Teacher of the Cosmic Darkness.

SCPRedMage
2007-09-30, 11:07 PM
Nah, just the non-euclidean bandsaw of Yug-Shoggoth, the Shop Teacher of the Cosmic Darkness.
I think I played a cleric of his, once...

Icewalker
2007-09-30, 11:13 PM
That would be awesome. The god involving non-euclidean geometry, letting you mess with physics :smallbiggrin:

...I should homebrew it.

But yeah, question answered. d3 = d6/2

darkriku2000
2007-10-02, 08:57 PM
thanks guys:smallamused:

Drider
2007-10-02, 09:22 PM
Cut a d6 in half using a bandsaw. From a single d6 you can get 2 d3s; 4 from a d12; and from a d20 you can get 2 d3s, a d5, a d7, and a d2.

That would require alot of precision, otherwise you might lose a couple sides, so aside from the d2, that's what you'd get

DraPrime
2007-10-02, 09:32 PM
You could just roll a d4, and if you get a 4 then just re-roll it.

Green Bean
2007-10-02, 10:19 PM
That would require alot of precision, otherwise you might lose a couple sides, so aside from the d2, that's what you'd get

I want you to think very carefully about the actual dimensions of a d6, and what dividing it in half would create. :smallamused: